Rotational Mechanics is one of the most important chapters in JEE Physics. In JEE Main 2024, 2 questions came from this chapter; JEE Advanced 2023 had 3 rotational problems. Mastering moment of inertia, angular momentum conservation, and rolling motion is essential for JEE 2027.
Moment of Inertia (I)
I = Sigma(mr²) for discrete masses | I = integral(r² dm) for continuous bodies
Analogue of mass for rotation. Depends on axis of rotation.
Standard Results (Memorise for JEE):
| Body | Axis | I |
|---|---|---|
| Thin rod (L, M) | Centre, perpendicular | ML2/12 |
| Thin rod | End, perpendicular | ML2/3 |
| Disc (R) | Central axis | MR2/2 |
| Disc | Diameter | MR2/4 |
| Ring (R) | Central axis | MR2 |
| Ring | Diameter | MR2/2 |
| Solid sphere | Diameter | 2MR2/5 |
| Hollow sphere | Diameter | 2MR2/3 |
| Solid cylinder | Central axis | MR2/2 |
| Hollow cylinder | Central axis | MR2 |
Theorems of Moment of Inertia
Parallel Axes Theorem: I = I_cm + Md2 (d = distance from CM axis)
Perpendicular Axes Theorem: I_z = I_x + I_y (for planar bodies only)
Torque and Angular Acceleration
Torque: tau = r x F (cross product) | Magnitude: tau = rF sin(theta)
Newton Law for Rotation: tau = I*alpha
Angular Momentum
L = I*omega (rigid body) | L = r x p (particle)
Conservation: When net torque = 0, L is conserved.
Classic: Ice skater pulls arms (I decreases, omega increases, L constant)
Rolling Motion Without Slipping
Condition: v = R*omega
KE_total = (1/2)mv2 + (1/2)I*omega2 = (1/2)mv2(1 + k2/R2)
Acceleration on incline: a = g sin(theta) / (1 + k2/R2)
Order reaching bottom (fastest first): Solid sphere > Solid cylinder > Hollow sphere > Hollow cylinder
Rolling Bodies Comparison
| Body | k2/R2 | % Rotational KE |
|---|---|---|
| Solid sphere | 2/5 | 28.6% |
| Solid cylinder | 1/2 | 33.3% |
| Hollow sphere | 2/3 | 40% |
| Hollow cylinder/Ring | 1 | 50% |
Practice MCQs – Rotational Mechanics
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Last updated: April 2026 | JEE Gurukul – Focused JEE preparation with concept clarity