📝 Online Quiz Engine
Daily Practice Sheet — 50 Questions
Take this quiz online with timer, mark-for-review, instant scorecard, percentile, and per-question explanations. CLAT scoring scheme: +1 / -0.25.
Daily MCQ Paper — 10 April 2026
50 questions across all sections. Use the practice interface to attempt; review answers and explanations after submission.
- Q1. The magnetic moment of a bar magnet of pole strength m and length 2l is
- m/2l
- 2ml
- m*l
- m/l
- Q2. A source moves towards a stationary observer with velocity vs. The apparent frequency f equals (v = sound speed, f0 = source frequency)
- f0 (v + vs)/v
- f0 v/(v – vs)
- f0 (v – vs)/v
- f0 v/(v + vs)
- Q3. The horizontal component of Earths magnetic field at the equator is
- Maximum
- Zero
- Equal to vertical component
- Negative
- Q4. In a stationary wave on a string fixed at both ends, the fundamental mode has
- One node and one antinode
- Two nodes and one antinode
- Two antinodes and one node
- Three nodes
- Q5. The number of beats per second when two tuning forks of frequencies 256 Hz and 260 Hz are sounded together is
- 2
- 4
- 8
- 256
- Q6. Curies law states that magnetic susceptibility of a paramagnetic material is
- Directly proportional to absolute temperature
- Inversely proportional to absolute temperature
- Independent of temperature
- Proportional to T squared
- Q7. The wave equation for a transverse wave on a string is given by y = A sin(kx – omega*t). Wave speed equals
- A*omega
- omega/k
- k*omega
- A/k
- Q8. The fundamental frequency of an organ pipe closed at one end of length L and sound speed v is
- v/(2L)
- v/(4L)
- v/L
- 2v/L
- Q9. An open organ pipe and a closed organ pipe of the same length will have fundamental frequencies in ratio
- 1:1
- 2:1
- 1:2
- 4:1
- Q10. Curie temperature of iron, above which it loses ferromagnetism, is approximately
- 770 K
- 1043 K
- 1300 K
- 1700 K
- Q11. A point charge q at the centre of a cube — total electric flux through the cube is
- q/ε₀
- q/(6ε₀)
- zero
- q/(8ε₀)
- Q12. In a balanced Wheatstone bridge (P,Q,R,S), the condition is
- P/Q = R/S
- P/R = Q/S
- P·Q = R·S
- PQRS = 1
- Q13. In an adiabatic process for an ideal gas
- PV = constant
- PV^γ = constant
- TV = constant
- P/T = constant
- Q14. A body is projected with velocity 20 m/s at 60° to horizontal. Time of flight (g=10):
- 2 s
- 3.46 s
- 4 s
- 1.73 s
- Q15. Young's modulus has dimensions of
- Force
- Pressure
- Energy
- Power
- Q16. The resonance frequency of a series LCR circuit with L = 2 H and C = 8 µF is approximately
- 40 Hz
- 25 Hz
- 100 Hz
- 400 Hz
- Q17. The Quality factor (Q) of a series LCR circuit at resonance is
- ω₀L/R
- R/ω₀L
- RC
- ω₀/R
- Q18. The Kolbe-Schmitt reaction converts sodium phenoxide and CO2 (under pressure) to
- Salicylaldehyde
- Salicylic acid
- Picric acid
- Phthalic acid
- Q19. Lucas reagent (anhydrous ZnCl2 + concentrated HCl) distinguishes alcohols. Tertiary alcohols give turbidity
- Immediately
- In about 5 minutes
- Only on warming
- Never
- Q20. Which test gives a silver mirror with aldehydes but not ketones
- Fehlings test
- Tollens test
- Lucas test
- Iodoform test
- Q21. The Reimer-Tiemann reaction converts phenol to
- Salicylaldehyde
- Benzaldehyde
- Salicylic acid
- Picric acid
- Q22. The Etard reaction converts toluene to benzaldehyde using
- PCC
- CrO2Cl2 in CS2
- KMnO4
- SeO2
- Q23. Fehlings solution gives a brick-red precipitate of which compound when treated with an aldehyde
- Cu
- Cu2O
- CuO
- Cu(OH)2
- Q24. The Rosenmund reduction converts an acyl chloride to an aldehyde using
- LiAlH4
- NaBH4
- H2 / Pd-BaSO4 (poisoned)
- Zn-Hg/HCl
- Q25. Hinsberg reagent (benzenesulphonyl chloride) is used to distinguish
- Alkyl halides
- 1°, 2°, 3° amines
- Alcohols
- Aldehydes from ketones
- Q26. The Sandmeyer reaction converts an aryldiazonium salt (ArN2+Cl-) to ArCl using
- CuCl/HCl
- Cu/HCl
- HCl alone
- SnCl2/HCl
- Q27. The Gattermann reaction differs from Sandmeyer in using
- CuCN
- Cu/HCl in place of CuCl/HCl
- HBF4
- HNO2
- Q28. In Friedel-Crafts alkylation, a major limitation is
- Failure with deactivated arenes (e.g., nitrobenzene)
- Polyalkylation due to product being more activated
- Carbocation rearrangements
- All of the above
- Q29. According to Le Chatelier's principle, increasing pressure on N2+3H2⇌2NH3 will
- Shift equilibrium left
- Shift equilibrium right (towards NH3)
- Have no effect
- Decompose NH3
- Q30. In cyclohexane, the chair conformation is preferred over the boat because
- Boat has more torsional strain (eclipsing) and flagpole interactions
- Chair has bond angles of exactly 120°
- Boat is planar
- Chair has more torsional strain
- Q31. The R/S configuration is assigned by the Cahn-Ingold-Prelog rules; priority is decided by
- Atomic number at the chiral centre
- Atomic mass only
- Bond length
- Polarity of substituent
- Q32. The magnitude of crystal field splitting in tetrahedral vs octahedral (with same metal/ligand) is
- Equal
- Δt = (4/9)Δo
- Δt = (9/4)Δo
- Δt = 2Δo
- Q33. Zeolites belong to the class of
- Borosilicates
- Aluminosilicates
- Carbonates
- Phosphates
- Q34. The diagonal relationship in periodic table is between
- Li-Be
- Li-Mg
- Be-B
- Na-Mg
- Q35. The general solution of cos x = cos alpha is
- x = n*pi + alpha
- x = 2n*pi +/- alpha
- x = n*pi +/- alpha
- x = (2n+1)*pi/2 + alpha
- Q36. In any triangle ABC, by the sine rule a/sin A equals
- R
- 2R
- 3R
- R/2
- Q37. The general solution of sin x = sin alpha is
- x = n*pi + alpha
- x = n*pi + (-1)^n * alpha
- x = 2n*pi + alpha
- x = n*pi – alpha
- Q38. The area of triangle ABC in terms of two sides and included angle is
- (1/2) a b sin C
- (1/2) a b cos C
- a b sin C
- (1/2) a b tan C
- Q39. The inradius r of a triangle is given by (s = semi-perimeter, Delta = area)
- Delta * s
- Delta / s
- s / Delta
- s * Delta
- Q40. The general solution of tan x = tan alpha is
- x = n*pi + alpha
- x = 2n*pi + alpha
- x = (2n+1)*pi/2 + alpha
- x = n*pi – alpha
- Q41. The circumradius R of triangle is
- a*b*c/(4*Delta)
- Delta/(a*b*c)
- 4*Delta/(a*b*c)
- a*b*c/Delta
- Q42. The exradius r1 opposite vertex A equals
- Delta/(s-a)
- Delta/s
- Delta/(s+a)
- (s-a)/Delta
- Q43. A man at the foot of a tower observes the angle of elevation of its top as 60°. After walking 100 m back the angle becomes 30°. Height of tower (m)
- 50
- 50*sqrt 3
- 100*sqrt 3
- 100/sqrt 3
- Q44. If A + B + C = pi (in a triangle), then tan A + tan B + tan C equals
- tan A tan B tan C
- sin A sin B sin C
- 1
- 0
- Q45. In the expansion of (1+x)¹¹, the two middle terms are
- T6 and T7
- T5 and T6
- T6 and T8
- T11 and T12
- Q46. The general equation x² + y² + 2gx + 2fy + c = 0 represents a real circle iff
- g² + f² – c > 0
- g² + f² – c = 0
- g² + f² – c < 0
- g + f + c > 0
- Q47. The shortest distance between two skew lines r = a₁+λb₁ and r = a₂+μb₂ is
- |(a₂-a₁)·(b₁×b₂)| / |b₁×b₂|
- |a₂-a₁|
- |b₁×b₂|
- |(a₂-a₁)×(b₁×b₂)|
- Q48. The angle between the lines y = 2x + 3 and y = -3x + 1 is given by
- tan⁻¹(1)
- tan⁻¹(5/5) = 45°
- tan⁻¹|(2-(-3))/(1+2(-3))| = tan⁻¹(1) = 45°
- tan⁻¹(7)
- Q49. The perpendicular distance from the point (3, -2) to the line 4x – 3y + 5 = 0 is
- 23/5
- 19/5
- 17/5
- 11/5
- Q50. The differential equation modelling Newton's law of cooling is
- dT/dt = −k(T − Ts)
- dT/dt = k·T
- dT/dt = −kT^2
- dT/dt = k(T + Ts)