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Daily Practice Sheet — 50 Questions
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Daily MCQ Paper — 9 April 2026
50 questions across all sections. Use the practice interface to attempt; review answers and explanations after submission.
- Q1. The magnetic moment of a bar magnet of pole strength m and length 2l is
- m/2l
- 2ml
- m*l
- m/l
- Q2. The horizontal component of Earths magnetic field at the equator is
- Maximum
- Zero
- Equal to vertical component
- Negative
- Q3. Curies law states that magnetic susceptibility of a paramagnetic material is
- Directly proportional to absolute temperature
- Inversely proportional to absolute temperature
- Independent of temperature
- Proportional to T squared
- Q4. The fundamental frequency of an organ pipe closed at one end of length L and sound speed v is
- v/(2L)
- v/(4L)
- v/L
- 2v/L
- Q5. In a stationary wave on a string fixed at both ends, the fundamental mode has
- One node and one antinode
- Two nodes and one antinode
- Two antinodes and one node
- Three nodes
- Q6. Curie temperature of iron, above which it loses ferromagnetism, is approximately
- 770 K
- 1043 K
- 1300 K
- 1700 K
- Q7. The number of beats per second when two tuning forks of frequencies 256 Hz and 260 Hz are sounded together is
- 2
- 4
- 8
- 256
- Q8. A source moves towards a stationary observer with velocity vs. The apparent frequency f equals (v = sound speed, f0 = source frequency)
- f0 (v + vs)/v
- f0 v/(v – vs)
- f0 (v – vs)/v
- f0 v/(v + vs)
- Q9. An open organ pipe and a closed organ pipe of the same length will have fundamental frequencies in ratio
- 1:1
- 2:1
- 1:2
- 4:1
- Q10. The wave equation for a transverse wave on a string is given by y = A sin(kx – omega*t). Wave speed equals
- A*omega
- omega/k
- k*omega
- A/k
- Q11. Kepler's third law states T² is proportional to
- a
- a²
- a³
- 1/a
- Q12. Two tuning forks of frequencies 256 Hz and 260 Hz produce beats at
- 2 Hz
- 4 Hz
- 8 Hz
- 256 Hz
- Q13. Magnetic dipole moment of a current loop of N turns, area A and current I is
- NIA
- I/A
- NA/I
- N/IA
- Q14. The Davisson-Germer experiment confirmed
- Particle nature of light
- Wave nature of electrons
- Quantization of charge
- Existence of neutron
- Q15. The dimensional formula of Planck's constant is
- [ML²T⁻¹]
- [MLT⁻¹]
- [ML²T⁻²]
- [MLT⁻²]
- Q16. Escape velocity from Earth's surface (R, g) is
- sqrt(gR)
- sqrt(2gR)
- sqrt(gR/2)
- 2sqrt(gR)
- Q17. A simple astronomical telescope in normal adjustment has objective focal length f_o and eyepiece f_e; its magnifying power is
- f_o + f_e
- f_o/f_e
- f_e/f_o
- f_o·f_e
- Q18. Lucas reagent (anhydrous ZnCl2 + concentrated HCl) distinguishes alcohols. Tertiary alcohols give turbidity
- Immediately
- In about 5 minutes
- Only on warming
- Never
- Q19. The Reimer-Tiemann reaction converts phenol to
- Salicylaldehyde
- Benzaldehyde
- Salicylic acid
- Picric acid
- Q20. The Sandmeyer reaction converts an aryldiazonium salt (ArN2+Cl-) to ArCl using
- CuCl/HCl
- Cu/HCl
- HCl alone
- SnCl2/HCl
- Q21. The Kolbe-Schmitt reaction converts sodium phenoxide and CO2 (under pressure) to
- Salicylaldehyde
- Salicylic acid
- Picric acid
- Phthalic acid
- Q22. Which test gives a silver mirror with aldehydes but not ketones
- Fehlings test
- Tollens test
- Lucas test
- Iodoform test
- Q23. Fehlings solution gives a brick-red precipitate of which compound when treated with an aldehyde
- Cu
- Cu2O
- CuO
- Cu(OH)2
- Q24. The Etard reaction converts toluene to benzaldehyde using
- PCC
- CrO2Cl2 in CS2
- KMnO4
- SeO2
- Q25. The Rosenmund reduction converts an acyl chloride to an aldehyde using
- LiAlH4
- NaBH4
- H2 / Pd-BaSO4 (poisoned)
- Zn-Hg/HCl
- Q26. The Gattermann reaction differs from Sandmeyer in using
- CuCN
- Cu/HCl in place of CuCl/HCl
- HBF4
- HNO2
- Q27. Hinsberg reagent (benzenesulphonyl chloride) is used to distinguish
- Alkyl halides
- 1°, 2°, 3° amines
- Alcohols
- Aldehydes from ketones
- Q28. Hess's law of constant heat summation is a consequence of
- First law
- Second law
- Third law
- Zeroth law
- Q29. Galvanic cell converts
- Electrical → chemical
- Chemical → electrical
- Heat → electrical
- Light → electrical
- Q30. A meso compound is one which
- Is optically active
- Has chiral centres but an internal plane of symmetry, hence optically inactive
- Has no chiral centres
- Is a racemic mixture
- Q31. Which actinide shows the maximum oxidation state of +7?
- U
- Np
- Pu
- Am
- Q32. Diborane (B₂H₆) has bonding involving
- Only 2c-2e bonds
- Two 3c-2e (banana) bonds + four 2c-2e bonds
- Only 3c-2e bonds
- Hydrogen bonds only
- Q33. Standard hydrogen electrode (SHE) potential is taken as
- 0.00 V
- 1.00 V
- -1.00 V
- 0.34 V
- Q34. Kohlrausch's law of independent migration of ions states that
- Lambda_m at infinite dilution = sum of ionic conductances
- Ionic mobility = constant
- Conductance increases with concentration
- None
- Q35. The general solution of cos x = cos alpha is
- x = n*pi + alpha
- x = 2n*pi +/- alpha
- x = n*pi +/- alpha
- x = (2n+1)*pi/2 + alpha
- Q36. The general solution of tan x = tan alpha is
- x = n*pi + alpha
- x = 2n*pi + alpha
- x = (2n+1)*pi/2 + alpha
- x = n*pi – alpha
- Q37. The general solution of sin x = sin alpha is
- x = n*pi + alpha
- x = n*pi + (-1)^n * alpha
- x = 2n*pi + alpha
- x = n*pi – alpha
- Q38. The circumradius R of triangle is
- a*b*c/(4*Delta)
- Delta/(a*b*c)
- 4*Delta/(a*b*c)
- a*b*c/Delta
- Q39. The inradius r of a triangle is given by (s = semi-perimeter, Delta = area)
- Delta * s
- Delta / s
- s / Delta
- s * Delta
- Q40. The area of triangle ABC in terms of two sides and included angle is
- (1/2) a b sin C
- (1/2) a b cos C
- a b sin C
- (1/2) a b tan C
- Q41. In any triangle ABC, by the sine rule a/sin A equals
- R
- 2R
- 3R
- R/2
- Q42. The exradius r1 opposite vertex A equals
- Delta/(s-a)
- Delta/s
- Delta/(s+a)
- (s-a)/Delta
- Q43. A man at the foot of a tower observes the angle of elevation of its top as 60°. After walking 100 m back the angle becomes 30°. Height of tower (m)
- 50
- 50*sqrt 3
- 100*sqrt 3
- 100/sqrt 3
- Q44. If A + B + C = pi (in a triangle), then tan A + tan B + tan C equals
- tan A tan B tan C
- sin A sin B sin C
- 1
- 0
- Q45. Sum of binomial coefficients in expansion of (1 + x)ⁿ is
- 2ⁿ
- 3ⁿ
- n²
- n!
- Q46. Equation of parabola with focus (a,0) and directrix x = -a is
- y² = 4ax
- x² = 4ay
- x² = -4ay
- y² = -4ax
- Q47. If A is a 3×3 matrix with |A| ≠ 0, then A⁻¹ equals
- adj(A)/|A|
- |A|·adj(A)
- adj(A)·|A|²
- (adj A)⁻¹
- Q48. In the expansion of (1+x)¹¹, the two middle terms are
- T6 and T7
- T5 and T6
- T6 and T8
- T11 and T12
- Q49. If y = f(g(x)), then dy/dx equals
- f'(g(x))
- g'(x)
- f'(g(x))·g'(x)
- f'(x)·g'(x)
- Q50. ∫ e^x dx =
- e^x + C
- e^x/x + C
- x·e^x + C
- e^(x+1)/(x+1) + C