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Daily Practice Sheet — 50 Questions
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Daily MCQ Paper — 8 April 2026
50 questions across all sections. Use the practice interface to attempt; review answers and explanations after submission.
- Q1. In Youngs double slit experiment with slit separation d and screen distance D, fringe width is
- lambda * D / d
- lambda * d / D
- D / (lambda * d)
- d / (lambda * D)
- Q2. In Youngs double slit experiment if the intensity from each slit is I0, the maximum intensity at the screen is
- I0
- 2 I0
- 4 I0
- sqrt(2) I0
- Q3. In single slit Fraunhofer diffraction, the first minimum occurs at angle satisfying
- b sin theta = lambda
- b sin theta = lambda / 2
- b sin theta = 2 lambda
- b cos theta = lambda
- Q4. Brewsters law states that at the polarising angle iB
- tan iB = mu
- sin iB = mu
- cos iB = mu
- cot iB = mu
- Q5. Maluss law gives the intensity transmitted through a polariser as I = I0 cos^2 theta where theta is angle between
- Light direction and polariser axis
- Polariser and analyser transmission axes
- Electric and magnetic field vectors
- Two coherent sources
- Q6. Einsteins photoelectric equation is
- h nu = phi + (1/2) m vmax^2
- h nu = phi – (1/2) m vmax^2
- h nu = phi + m vmax^2
- h nu = (1/2) m vmax^2
- Q7. de Broglie wavelength of a particle of momentum p is
- h * p
- h / p
- p / h
- h / (p^2)
- Q8. The mass defect Delta m and binding energy E of a nucleus are related by
- E = Delta m * c
- E = Delta m * c^2
- E = Delta m / c^2
- E = Delta m * c^3
- Q9. The radioactive decay law N = N0 e^(-lambda t) gives half-life t1/2 equal to
- 1 / lambda
- ln 2 / lambda
- lambda / 2
- 2 lambda
- Q10. Stable nuclei in the binding-energy-per-nucleon curve peak around mass number
- A = 8
- A = 28
- A = 56
- A = 200
- Q11. The fundamental frequency of an organ pipe closed at one end of length L and sound speed v is
- v/(2L)
- v/(4L)
- v/L
- 2v/L
- Q12. Total mechanical energy of a satellite in circular orbit of radius r is
- -GMm/r
- -GMm/(2r)
- +GMm/(2r)
- -GMm/(4r)
- Q13. Brewster's angle for a glass of refractive index 1.5 is approximately
- 45°
- 56.3°
- 60°
- 33°
- Q14. The efficiency of a Carnot engine working between T1 (hot) and T2 (cold) is
- 1 − T2/T1
- T1/T2 − 1
- T2/T1
- (T1−T2)/T2
- Q15. For a rigid body rotating about a fixed axis, angular momentum L and angular velocity ω are related by
- L = Iω
- L = mvω
- L = ω/I
- L = I²ω
- Q16. The time period of a simple pendulum of length L (small angle) is
- 2π√(g/L)
- 2π√(L/g)
- π√(L/g)
- (1/2π)√(L/g)
- Q17. The horizontal component of Earths magnetic field at the equator is
- Maximum
- Zero
- Equal to vertical component
- Negative
- Q18. Hell-Volhard-Zelinsky reaction effects which transformation
- Alpha-halogenation of carboxylic acids
- Beta-halogenation of alcohols
- Aromatic ring nitration
- Reduction of esters
- Q19. Fischer esterification involves carboxylic acid and alcohol in presence of
- NaOH
- Conc H2SO4 (acid catalyst)
- LiAlH4
- Zn dust
- Q20. Carboxylic acids on reduction with LiAlH4 yield
- Aldehydes
- Primary alcohols
- Secondary alcohols
- Ketones
- Q21. Decarboxylation of sodium salts of carboxylic acids with sodalime gives
- Higher hydrocarbons
- Hydrocarbons with one less carbon
- Aldehydes
- Alcohols
- Q22. Schiemann reaction prepares aryl fluorides from diazonium salts via
- Direct reaction with KF
- HBF4 + thermal decomposition
- CuF/HF
- HF/peroxide
- Q23. Kolbe-Schmitt reaction is the carboxylation of sodium phenoxide with CO2 yielding primarily
- Benzoic acid
- Salicylic acid
- Phthalic acid
- Acetic acid
- Q24. Sandmeyer reaction converts an aryl diazonium salt to aryl halide using
- CuCl/HCl or CuBr/HBr
- HBF4 thermal
- H3PO2
- NaOH
- Q25. Reaction of arenediazonium salt with hypophosphorous acid (H3PO2) results in
- Replacement of N2+ by H
- Replacement of N2+ by OH
- Coupling
- Reduction to phenylhydrazine
- Q26. Coupling of diazonium salt with phenol in mildly alkaline medium gives
- Methyl orange
- para-Hydroxyazobenzene
- Aniline yellow
- Indigo
- Q27. Liebermanns nitroso test is a confirmatory test for
- Aldehydes
- Phenols
- Primary amines
- Carboxylic acids
- Q28. The Kolbe-Schmitt reaction converts sodium phenoxide and CO2 (under pressure) to
- Salicylaldehyde
- Salicylic acid
- Picric acid
- Phthalic acid
- Q29. Which test gives a silver mirror with aldehydes but not ketones
- Fehlings test
- Tollens test
- Lucas test
- Iodoform test
- Q30. In Friedel-Crafts alkylation, a major limitation is
- Failure with deactivated arenes (e.g., nitrobenzene)
- Polyalkylation due to product being more activated
- Carbocation rearrangements
- All of the above
- Q31. In the aldol condensation, the alpha-hydrogen of a carbonyl compound is removed by a
- Strong acid (H₂SO₄)
- Mild base (OH⁻ or alkoxide)
- Free radical initiator
- Lewis acid AlCl₃
- Q32. According to VSEPR, the shape of XeF4 is
- Tetrahedral
- Square planar
- See-saw
- T-shape
- Q33. Henry's law constant has units of
- Pressure
- Pressure/concentration or pressure/mole-fraction
- Concentration
- Dimensionless
- Q34. LiCl is more covalent than NaCl primarily due to
- Smaller size of Li+
- Higher electronegativity of Li
- Polarising power of Li+ (Fajans rules)
- Li being lighter
- Q35. Principal value branch of cos^-1 x is
- [-pi/2, pi/2]
- [0, pi]
- (0, pi)
- [-pi, 0]
- Q36. Principal value branch of sin^-1 x is
- [0, pi]
- [-pi/2, pi/2]
- [-pi, pi]
- (0, pi)
- Q37. 2 tan^-1 x equals (for |x| < 1)
- tan^-1 (2x / (1 – x^2))
- tan^-1 (2x / (1 + x^2))
- sin^-1 (1 – x^2)
- cos^-1 (2x)
- Q38. Rolles theorem requires the function to be
- Continuous on [a,b], differentiable on (a,b) and f(a) = f(b)
- Only continuous on [a,b]
- Only differentiable on (a,b)
- Monotonic on [a,b]
- Q39. Lagranges Mean Value Theorem guarantees existence of c in (a,b) such that
- f(c) = (f(b)-f(a))/(b-a)
- f(c) = 0
- f(c) = (f(b)+f(a))/2
- f(c) = 1
- Q40. Derivative of log(x) with respect to x (natural logarithm) is
- 1/x
- x
- log x
- e^x
- Q41. If x = a cos t and y = a sin t, then dy/dx equals
- -cot t
- -tan t
- tan t
- cot t
- Q42. Order and degree of differential equation (d^2 y/dx^2)^3 + (dy/dx)^2 + y = 0 are
- 2 and 3
- 3 and 2
- 2 and 1
- 3 and 3
- Q43. Newtons law of cooling states that dT/dt is proportional to
- (T – T0)
- (T0 – T)
- -(T – T0)
- T^2
- Q44. Solution of differential equation dy/dx + y = 0 is
- y = C e^x
- y = C e^(-x)
- y = Cx
- y = C/x
- Q45. The length of the latus rectum of the parabola y² = 16x is
- 4
- 8
- 16
- 32
- Q46. Sum of binomial coefficients in expansion of (1 + x)ⁿ is
- 2ⁿ
- 3ⁿ
- n²
- n!
- Q47. The number of ways to arrange the letters of MISSISSIPPI is
- 11!/(4! 4! 2!)
- 11!
- 11!/(4! 2!)
- 11!/2!
- Q48. Length of latus rectum of y² = 16x is
- 4
- 8
- 16
- 32
- Q49. The eccentricity of the ellipse x²/25 + y²/9 = 1 is
- 3/5
- 4/5
- 5/3
- 5/4
- Q50. Sum of squares 1^2 + 2^2 + … + n^2 equals
- n(n+1)/2
- n(n+1)(2n+1)/6
- [n(n+1)/2]^2
- n^3